Title: Openai/6919ca73-5614-8009-bb7f-6ff22c9d2193 - freem URL Source: https://freemwiki.com/index.php?mobileaction=toggle_view_mobile&title=Openai%2F6919ca73-5614-8009-bb7f-6ff22c9d2193 Markdown Content: _This conversation was exported from ChatGPT_[[1]](https://freemwiki.com/index.php?mobileaction=toggle_view_mobile&title=Openai%2F6919ca73-5614-8009-bb7f-6ff22c9d2193#cite_note-1) ## gpt-5-t-mini[edit](https://freemwiki.com/index.php?title=Openai/6919ca73-5614-8009-bb7f-6ff22c9d2193&action=edit§ion=1 "Edit section: gpt-5-t-mini") ### User: solve this[edit](https://freemwiki.com/index.php?title=Openai/6919ca73-5614-8009-bb7f-6ff22c9d2193&action=edit§ion=2 "Edit section: User: solve this") solve this ### Assistant: Answer: x80∘\displaystyle x80^\circx80∘.[edit](https://freemwiki.com/index.php?title=Openai/6919ca73-5614-8009-bb7f-6ff22c9d2193&action=edit§ion=3 "Edit section: Assistant: Answer: x80∘\displaystyle x80^\circx80∘.") Answer: x=80∘\displaystyle x=80^\circx=80∘. Sketch of a short solution (clean numeric / trig setup): Place the square with A=(0,1),B=(1,1),C=(1,0),D=(0,0)A=(0,1),B=(1,1),C=(1,0),D=(0,0)A=(0,1),B=(1,1),C=(1,0),D=(0,0). Let E=(e,0)E=(e,0)E=(e,0) and F=(1,1−t)F=(1,1-t)F=(1,1−t) (so t∈(0,1)t\in(0,1)t∈(0,1)). Angle at AAA between AE→=(e,−1)\overrightarrow{AE}=(e,-1)AE=(e,−1) and AF→=(1,−t)\overrightarrow{AF}=(1,-t)AF=(1,−t) is 45∘45^\circ45∘, so cos⁡45∘=(e)(1)+(−1)(−t)e2+11+t2=e+te2+11+t2.\cos45^\circ=\frac{(e)(1)+(-1)(-t)}{\sqrt{e^2+1}\sqrt{1+t^2}}=\frac{e+t}{\sqrt{e^2+1}\sqrt{1+t^2}}.cos45∘=e2+1​1+t2​(e)(1)+(−1)(−t)​=e2+1​1+t2​e+t​. Angle at FFF between the vertical BFBFBF and FE→=(e−1,−(1−t))\overrightarrow{FE}=(e-1,-(1-t))FE=(e−1,−(1−t)) gives cos⁡70∘=1−t(1−e)2+(1−t)2.\cos70^\circ=\frac{1-t}{\sqrt{(1-e)^2+(1-t)^2}}.cos70∘=(1−e)2+(1−t)2​1−t​. Solving these two equations (one can do it numerically or with algebraic manipulation) yields e≈0.17632698,t≈0.70020754.e\approx0.17632698,\qquad t\approx0.70020754.e≈0.17632698,t≈0.70020754. Finally the desired angle at EEE (between EA→=(−e,1)\overrightarrow{EA}=(-e,1)EA=(−e,1) and EF→=(1−e, 1−t)\overrightarrow{EF}=(1-e,\,1-t)EF=(1−e,1−t)) evaluates to ∠AEF≈80∘.\angle AEF \approx 80^\circ.∠AEF≈80∘. So x=80∘x=80^\circx=80∘. ## References[edit](https://freemwiki.com/index.php?title=Openai/6919ca73-5614-8009-bb7f-6ff22c9d2193&action=edit§ion=4 "Edit section: References") 1. [↑](https://freemwiki.com/index.php?mobileaction=toggle_view_mobile&title=Openai%2F6919ca73-5614-8009-bb7f-6ff22c9d2193#cite_ref-1 "Jump up")["Solve angle problem"](https://chatgpt.com/share/6919ca73-5614-8009-bb7f-6ff22c9d2193). ChatGPT. Retrieved 2025-11-16.