Jump to content
Main menu
Main menu
move to sidebar
hide
Navigation
Main page
Recent changes
Random page
freem
Search
Search
Appearance
Create account
Log in
Personal tools
Create account
Log in
Pages for logged out editors
learn more
Contributions
Talk
Editing
Openai/6897769e-4ee4-800f-aba5-69cca34f701c
(section)
Add languages
Page
Discussion
English
Read
Edit
Edit source
View history
Tools
Tools
move to sidebar
hide
Actions
Read
Edit
Edit source
View history
General
What links here
Related changes
Special pages
Page information
Appearance
move to sidebar
hide
Warning:
You are not logged in. Your IP address will be publicly visible if you make any edits. If you
log in
or
create an account
, your edits will be attributed to your username, along with other benefits.
Anti-spam check. Do
not
fill this in!
=== Assistant: Nice — thanks for asking me to run that numeric check. === Nice — thanks for asking me to run that numeric check. I did a short, careful numerical survey comparing the golden angle (from the Golden Ratio / Fibonacci construction) to the inverse fine-structure constant 1/α and to “Fibonacci-complement” angles formed the way you described. I show the numbers below and then a short interpretation and suggested next steps. ===== - 1/α (CODATA-ish value used) = 137.035999084 ===== * Golden angle (360° × (1 − 1/φ)) = 137.507764050° * Difference (golden angle − 1/α) ≈ 0.471765°, i.e. ~0.344% of 1/α. I also computed the “360 − 360·(Fₙ/Fₙ₊₁)” complements for consecutive Fibonacci pairs (F₆/F₇ through F₁₅/F₁₆). As n increases those complements converge to the golden angle, and their difference from 1/α settles close to the value above (~0.34% of 1/α). Example rows: | | | | | | | --- | --- | --- | --- | --- | | | | | | | | | | | | | | | | | | | (You’ll see the complements approach 137.507764… and the difference to 1/α approaches ≈ +0.4716°.) ===== - The golden angle and 1/α are close (difference ≈ 0.47°), but they are not equal within high precision. The discrepancy (~0.34%) is small but definitely physically non-negligible for a fundamental constant. ===== * The Fibonacci trick (using consecutive Fibonacci ratios) just converges to the golden angle, so it cannot by itself produce the exact value of 1/α — at best it gives a near value (the golden angle). * That near-equality is suggestive: either there is a real geometric relation with a correction term (i.e., α involves the golden-angle geometry plus a small correction arising from more detailed physics), or the similarity is a numerical coincidence (plausible — small dimensionless % differences crop up a lot). * Because α is dimensionless and derived from e²/(4πϵ₀ħc), a geometric explanation would need to show how those physical constants (charge, ħ, c, permittivity, or vacuum structure) produce a factor near the golden-angle construction. QAT’s spherical geometry idea gives a plausible mechanism to look for such corrections, but the observed numeric mismatch means we need an explicit geometric derivation (or a small correction term) to claim equality. ===== Pick one and I’ll run it next: ===== # Search for a simple analytic correction so that 1/α ≈ (golden angle) − ε, with ε expressed as a small simple function of π, e, or rational combination of φ (try linear combos, rational approximations). I can run a short search for low-integer rational combinations that reduce the residual (e.g., a·φ + b·π + c fits). # Do a constrained numeric optimisation: try to express 1/α as a small integer/rational-weighted sum of a small basis {φ, π, ln(2), e} and report best low-complexity approximations (with penalties for large integers). # Move from numerics to geometry: attempt a short derivation that links e², ħ/2π, c, and 4πr² to an angular geometry parameter and see if a small geometric correction naturally appears (this is more symbolic/analytical and will take longer). # Keep exploring the Fibonacci → golden-angle route but try to model a plausible physical correction from QAT (e.g., spherical-surface discrete sampling, finite-size effect, or charge-distribution asymmetry) and estimate the size of that correction numerically. If you want, I can now: * run option (1) or (2) and produce candidate simple formulae (quick numeric search), or * start sketching a short symbolic argument for how a small geometric correction might arise in QAT (option 3). Which would you prefer? (I can proceed automatically with a low-complexity numeric search first if you’d like.)
Summary:
Please note that all contributions to freem are considered to be released under the Creative Commons Attribution-ShareAlike 4.0 (see
Freem:Copyrights
for details). If you do not want your writing to be edited mercilessly and redistributed at will, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource.
Do not submit copyrighted work without permission!
Cancel
Editing help
(opens in new window)