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Openai/695d09e5-7848-8005-85a0-7c1e2c1cf8c2
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==== 7️⃣ 〈bn〉第7項 × 〈a(22/7)n〉第h項 = 完全平方數? ==== 題意: * 〈bn〉 = 7,21,63,189,… → 第7項 = 7⋅36=51037 \cdot 3^6 = 51037⋅36=5103 * h 六位數由 〈a(22/7)n〉第2到7項組成(提示前 7 項:3,1,4,2,8,5,7 → 2→7 位) * 〈a(22/7)n〉第 h 項 = 4(mod 6 計算得到) 步驟: # 計算 〈bn〉第7項 = 5103 # 〈a(22/7)n〉第 h 項 = 4 # 相乘: 5103×4=204125103 \times 4 = 204125103×4=20412 * 20412 不是完全平方數 ❌ 所以這題錯誤 ===== 總結 ===== | 題號 | 判斷 | | --- | ---- | | 5️⃣ | ✅ 正確 | | 6️⃣ | ✅ 正確 | | 7️⃣ | ❌ 錯誤 | * 正確數量 = 2️⃣+4️⃣之前正確選項 + 5️⃣+6️⃣ = 4 個 * ✅ 答案:4 個正確 如果你願意,我可以幫你畫一個 〈a(22/7)n〉 mod 6 循環對照表,把 α、β、h 這些位置一眼就看出來,比純文字還直觀。 你想要我畫嗎?
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