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== gpt-5-1 == === User: Let's do some investment math. === Let's do some investment math. Assume someone contributes $12,500 per month into an investment for a total of 5 years. At the end of that accumulation phase, they will then draw $7,000 per month for 12 years. What is the minimum annual growth rate of this investment so that the money doesn't run out before 12 years are up? === Assistant: Short answer: 3.6% annual return nominal, assuming monthly compounding. === Short answer: ~3.6% annual return (nominal), assuming monthly compounding. Below is the clean derivation. You contribute: * $12,500 per month for 60 months * Then withdraw $7,000 per month for 144 months Let: * rrr = annual growth rate * i=r/12i = r/12i=r/12 = monthly growth rate ===== 1. Future value after 5-year accumulation ===== Contributions are an ordinary annuity: FVcontrib=12,500×(1+i)60−1iFV_{\text{contrib}} = 12{,}500 \times \frac{(1+i)^{60} - 1}{i}FVcontrib=12,500×i(1+i)60−1 ===== 2. Value needed at the start of the withdrawal phase ===== Withdrawals are also an ordinary annuity: FVneeded=7,000×1−(1+i)−144iFV_{\text{needed}} = 7{,}000 \times \frac{1 - (1+i)^{-144}}{i}FVneeded=7,000×i1−(1+i)−144 We want: FVcontrib≥FVneededFV_{\text{contrib}} \ge FV_{\text{needed}}FVcontrib≥FVneeded ===== Solving numerically ===== Testing a few candidate annual rates: | Annual rate | Result | | ----------- | ------------------------------------------ | | 3.0% | Falls short (≈ $810k$ vs needed $848k$) | | 3.5% | Slightly short (≈ $818k$ vs needed $823k$) | | 3.6% | Just meets (≈ $821k$ vs needed $819k$) | | 4.0% | Safely exceeds | Thus the crossover is almost exactly: : ≈ 3.6% annual growth rate (nominal), with monthly compounding At 3.6%, the money lasts just long enough to fully cover the 12 years of withdrawals without depleting early. If you want, I can also: * Graph the funded ratio vs rate * Solve exactly using IRR-style methods * Compare monthly vs annual compounding * Add taxes or inflation for real returns
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