Editing Openai/691e301d-9ef8-800a-b179-3a4e29e49fe1


{{DISPLAYTITLE:Capacitor impedance calculation}}

''This conversation was exported from ChatGPT''<ref>{{cite web|title=Capacitor impedance calculation|url=https://chatgpt.com/share/691e301d-9ef8-800a-b179-3a4e29e49fe1|publisher=ChatGPT|access-date=2025-11-20}}</ref>

== gpt-5-1 ==
=== User: What is the impedance of an 0.1uF capacitor at 50Hz? ===
What is the impedance of an 0.1uF capacitor at 50Hz?

=== Assistant: To find the impedance of a capacitor, use: ===
To find the impedance of a capacitor, use:

ZC=1j 2πfCZ_C = \frac{1}{j \, 2\pi f C}ZC=j2πfC1
We usually give the magnitude:

∣ZC∣=12πfC|Z_C| = \frac{1}{2\pi f C}∣ZC∣=2πfC1
Given:
* C=0.1 μF=1×10−7 FC = 0.1\,\mu\text{F} = 1\times10^{-7}\,\text{F}C=0.1μF=1×10−7F
* f=50 Hzf = 50\,\text{Hz}f=50Hz

Compute:

∣ZC∣=12π⋅50⋅1×10−7|Z_C| = \frac{1}{2\pi \cdot 50 \cdot 1\times10^{-7}}∣ZC∣=2π⋅50⋅1×10−71
∣ZC∣=13.14159×10−5|Z_C| = \frac{1}{3.14159 \times 10^{-5}}∣ZC∣=3.14159×10−51
∣ZC∣≈31831 Ω|Z_C| \approx 31831\,\Omega∣ZC∣≈31831Ω
So:

===== Impedance (magnitude): ~31.8 kΩ =====

===== Complex form: =====

ZC≈−j 31.8 kΩZ_C \approx -j\,31.8\,\text{k}\OmegaZC≈−j31.8kΩ
(It's purely reactive and negative imaginary.)

== References ==
<references />


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